Friday , April 19 2019

JEE Main 2017 Results

JEE Main 2017 results: The percentage is attained from the marks acquired divided by the total number of marks and multiplied by 100.


JEE Main 2017 results: Students were hailed with a pleasurable surprise as the Central Board of Secondary Education (CBSE) confirmed the JEE Main 2017 results yesterday and the cut-off for JEE advanced was surprisingly low this year. The cut-off marks for the general category is about 81, which carries a twist in prior forecasts which had believed the cut-off would be amid 95 to 105 this year.

Read More: Goa Board Class 12th Exams 2017 Results Released

Above one lakh students are qualified for JEE Advanced from the usual rank list. The Joint Entrance Exam 2017 main exams were conducted on April 2, 8 and 9, this year.


“The cut off marks was low this year because of the level of toughness of the mathematics paper,” speaks Venkat Ramana, JEE exam head of TIME Hyderabad. This year, the JEE main marks will not be made on the basis of the class 12 board marks. The admissibility for JEE advanced will totally be dependent on the JEE main score and ranks.

The previous year, the JEE main cut-off was 100 and OBC, SC, and ST categories was at 70, 52 and 48 correspondingly. The cut-off in the year 2015 was 105 for general category students and for OBC, SC and ST category students it was 70, 50 and 44 correspondingly. 

Around 10.20 lakh students partaken in the JEE main examination this year. On the basis of JEE Main rankings, around 2.20 lakh top scorers will be given possibility to join in JEE Advanced 2017. The qualified applicants have to get listed in JEE Advanced.

D Ankita, a candidate who wasn’t supposing to score well is amazing the way low cut-off. “I felt mathematics would bring down my score but I have done it to the JEE Advanced,” said she.

The JEE Advanced paper will be led by the Indian Institute of Technology (IIT), Madras on 21st May, 2017. To be qualified for advanced applicants will be needed to have scored minimum 75 percent in their class 12 board exams (65 percent for SC and ST candidates).

Applicants can compute their score grounded on their percentage or their percentile. The percentage is evaluated from the marks divided by the total number of marks and multiplied by 100. The percentile is evaluated with the total number of marks of all five subjects to define the applicant’s position in the board. The percentile is used to compute the normalized score.

While choosing the candidates from the final list after advanced, the succeeding order will be followed:

jee (1)

The top 2,20,000 scorers will be allowable to appear for the advanced paper and applicants should have got at least 50.5 percent. This percentage differs for reserved categories — 27 percent for OBC and NCL, 15 percent for SC and 7.5 per cent for ST.

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